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0.3333333h^2-3.3333333h+8=0
a = 0.3333333; b = -3.3333333; c = +8;
Δ = b2-4ac
Δ = -3.33333332-4·0.3333333·8
Δ = 0.44444528888889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.3333333)-\sqrt{0.44444528888889}}{2*0.3333333}=\frac{3.3333333-\sqrt{0.44444528888889}}{0.6666666} $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.3333333)+\sqrt{0.44444528888889}}{2*0.3333333}=\frac{3.3333333+\sqrt{0.44444528888889}}{0.6666666} $
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